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3x^2+5=2x^2+1
We move all terms to the left:
3x^2+5-(2x^2+1)=0
We get rid of parentheses
3x^2-2x^2-1+5=0
We add all the numbers together, and all the variables
x^2+4=0
a = 1; b = 0; c = +4;
Δ = b2-4ac
Δ = 02-4·1·4
Δ = -16
Delta is less than zero, so there is no solution for the equation
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